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(11y^2+57y+44)=0
We get rid of parentheses
11y^2+57y+44=0
a = 11; b = 57; c = +44;
Δ = b2-4ac
Δ = 572-4·11·44
Δ = 1313
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-\sqrt{1313}}{2*11}=\frac{-57-\sqrt{1313}}{22} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+\sqrt{1313}}{2*11}=\frac{-57+\sqrt{1313}}{22} $
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